16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4f0,{"@context":"https://schema.org","@type":"Quiz","name":"Ts Eamcet 2024 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ts-eamcet/questions/2024/physics/waves/m6p8ti98","educationalLevel":"Entrance exam preparation","about":"Ts Eamcet / Physics / Waves","hasPart":{"@type":"Question","name":"Ts Eamcet 2024 Waves PYQ with Solution","text":"Two closed pipes when sounded simultaneously in their fundamental modes produce 6 beats per second. If the length of the shorter pipe is 150 cm , then the length of the longer pipe is (Speed of sound in air =336 \\mathrm{~ms}^{-1} )","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Given, Beat frequency, f_{\\text {beat }}=6 \\mathrm{~Hz} Length of the shorter pipe, L_{1}=150 \\mathrm{~cm} =1.5 \\mathrm{~m} Speed of sound in air, v=336 \\mathrm{~m} / \\mathrm{s} For a closed loop, fundamental frequency is given by, f=\\frac{v}{4 L} For the shorter pipe L_{1} , f_{1}=\\frac{336}{4 \\times 1.5}=\\frac{336}{6}=56 \\mathrm{~Hz} Let the length of longer pipe be L_{2} and frequency be f_{2} . Since the pipes produces 6 beats per second when sound together: \\left|f_{1}-f_{2}\\right|=6 There..."}}}18:T555,

Given,

Beat frequency, $ f_{\text {beat }}=6 \mathrm{~Hz} $

Length of the shorter pipe, $ L_{1}=150 \mathrm{~cm} $

$ =1.5 \mathrm{~m} $

Speed of sound in air, $ v=336 \mathrm{~m} / \mathrm{s} $

For a closed loop, fundamental frequency is

Waves

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