16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4fd,{"@context":"https://schema.org","@type":"Quiz","name":"Ts Eamcet 2024 Center Of Mass PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ts-eamcet/questions/2024/physics/center-of-mass/m6p8uhbe","educationalLevel":"Entrance exam preparation","about":"Ts Eamcet / Physics / Center Of Mass","hasPart":{"@type":"Question","name":"Ts Eamcet 2024 Center Of Mass PYQ with Solution","text":"A meter scale is balanced on a knife edge at its centre. When two coins, each of mass 9 g are kept one above the other at the 10 cm mark, the scale is found to be balanced at 35 cm . The mass of the meter scale is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"Let mass of meter scale be m . Mass of each coin =9 \\mathrm{~g} Total mass of coin =18 \\mathrm{~g} Length of meter scale =100 \\mathrm{~cm} The new balance point is at 35 cm The torque due to the coins placed at the 10 cm mark Distance from the new balance point to the coins =(35-10) \\mathrm{cm} =25 \\mathrm{~cm} Torque due to coins =F \\cdot r=m g r=18 \\times g \\times 25 The centre of mass of the meter scale is at its mid-point ( 50 cm mark). Distance from the new balance point to the =(50-35) \\m..."}}}18:T5cb,

Let mass of meter scale be $ m $.

Mass of each coin $ =9 \mathrm{~g} $

Total mass of coin $ =18 \mathrm{~g} $

Length of meter scale $ =100 \mathrm{~cm} $

The new balance point is at 35 cm

The torque due to the coins plac

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