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Quadratic Equations

TG EAPCET 2024 (Online) 10th May Morning Shift

MCQ+1 / -02024
$\alpha, \beta$ are the real roots of the equation $12 x^{\frac{1}{3}}-25 x^{\frac{1}{6}}+12=0$. If $\alpha>\beta$, then $6 \sqrt{\frac{\alpha}{\beta}}=$

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