Ts EamcetIndefinite IntegrationTG EAPCET 2024 (Online) 10th May Evening ShiftMCQ+1 / -02024$ \int \frac{1}{x^{m} \sqrt[m]{x^{m}+1}} d x =$A$\frac{1}{m-1}\left(\frac{\sqrt[m]{x^{m}+1}}{x}\right)^{m}+C$B$\frac{-1}{m-1}\left(\frac{\sqrt[m]{x^{m}+1}}{x}\right)^{m-1}+C$C$\frac{-1}{m}\left(\frac{\sqrt[m]{x^{m}+1}}{x}\right)^{m}+C$D$\frac{1}{m}\left(\frac{\sqrt[m-1]{x^{m}+1}}{x}\right)^{m}+C$Check AnswerClear SelectionReveal AnswerShow Explanation
