Ts EamcetDifferentiationTG EAPCET 2024 (Online) 9th May Evening ShiftMCQ+1 / -02024If $y=44 x^{45}+45 x^{-44}$, then $y^n=$A$\frac{1980 y}{x^2}$.B$\frac{2020 x^2}{y}$C$\frac{2024 y}{x^2}$D$\frac{1990 x^2}{y}$Check AnswerClear SelectionReveal AnswerShow Explanation