Ts EamcetApplication Of DerivativesTG EAPCET 2024 (Online) 10th May Morning ShiftMCQ+1 / -02024The equation of the normal drawn to the curve $y^3=4 x^5$ at the point $(4,16)$ isA$20 x+3 y=128$B$20 x-3 y=32$C$3 x-20 y+308=0$D$3 x+20 y=332$Check AnswerClear SelectionReveal AnswerShow Explanation