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Ts Eamcet

Probability

TS EAMCET 2023 (Online) 14th May Morning Shift

MCQ+1 / -02023

A random variable $X$ has the following probability distribution


$$ \begin{array}{|c|l|l|l|l|l|l|l|l|} \hline \boldsymbol{X}=\boldsymbol{x} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline \boldsymbol{P}(\boldsymbol{X}=\boldsymbol{x}) & 0.15 & 0.23 & k & 0.10 & 0.20 & 0.08 & 0.07 & 0.05 \\ \hline \end{array} $$


For the events $E=\{x / x$ is a prime number $\}$ and $F=\{x / x<4\}$, then $P(E \cup F)=$

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