Ts EamcetDifferentiationTS EAMCET 2023 (Online) 12th May Morning ShiftMCQ+1 / -02023If $\tan y=\cot \left(\frac{\pi}{4}-x\right)$, then $\frac{d y}{d x}=$A$\frac{\operatorname{cosec}^2\left(\frac{\pi}{4}-x\right)}{1+\cot ^2\left(\frac{\pi}{4}+x\right)}$B$\frac{-\operatorname{cosec}^2\left(\frac{\pi}{4}-x\right)}{\sec ^2 y}$C$\frac{\operatorname{cosec}^2\left(\frac{\pi}{4}-x\right)}{1+\tan ^2\left(\frac{\pi}{4}+x\right)}$D$\frac{\sec ^2\left(\frac{\pi}{4}+x\right)}{1+\tan ^2\left(\frac{\pi}{4}+x\right)}$Check AnswerClear SelectionReveal AnswerShow Explanation
