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Circle

TS EAMCET 2023 (Online) 12th May Evening Shift

MCQ+1 / -02023

The equation of the line perpendicular to the radical axis of two circles $x^2+y^2-5 x+6 y+12=0$, $x^2+y^2+6 x-4 y-14=0$ and passing through $(1,1)$ is

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