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Binomial Theorem

TS EAMCET 2023 (Online) 14th May Evening Shift

MCQ+1 / -02023

If $\sum_{r=0}^{20}{ }^{20+r} C_r=\frac{p}{q}{ }^{40} C_{20}$ and GCD of $(p, q)=1$, then $p^2-q^2=$


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