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Ionic Equilibrum

TS EAMCET 2023 (Online) 14th May Evening Shift

MCQ+1 / -02023

At 298 K the molar solubility of $\mathrm{Cd}(\mathrm{OH})_2$ in $0.1 \mathrm{M} \mathrm{KOH}_{\mathrm{OH}}$ solution is $x \times 10^{-y}$. The values of $x$ and $y$ are respectively.


(At $298 \mathrm{~K}, K_{s p}$ of $\mathrm{Cd}(\mathrm{OH})_2=2.5 \times 10^{-14}$ )


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