Ts Eamcet
Parabola
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ+1 / -02022
If $x^2=8 a y$ is the transformed equation of $x^2-4 y+6 x+15=0$ when the origin is shifted to the point $(\alpha, \beta)$ by translation of axes, then $2 \alpha+8 \beta^2=$
