Ts Eamcet
Hyperbola
TS EAMCET 2022 (Online) 19th July Evening Shift
MCQ+1 / -02022
If $e_1$ is the eccentricity of the hyperbola $x=\sec \theta$, $y=\sqrt{2} \tan \theta$ and $e_2$ is the eccentricity of the hyperbola $x=\sqrt{2} \sec \theta$ and $y=\tan \theta$, then $\frac{e_2^2}{e_1^2}=$
