Ts Eamcet
Hyperbola
TS EAMCET 2022 (Online) 18th July Evening Shift
MCQ+1 / -02022
Let $S$ be the focus of the hyperbola $\frac{x^2}{16}-\frac{y^2}{9}=1$ lying on the positive $X$ - axis and $P\left(5, y_1\right)$ be point on the hyperbola. Then $S P=$
