Differential Equations

$1+\left(\frac{d y}{d x}\right)^2=\frac{r^2}{(y-3)^2}$

$1+\left(\frac{d y}{d x}\right)^2=\frac{r^2}{y-3}$

$\left(\frac{d y}{d x}\right)^2=\frac{r^2}{(y-3)^2}$

$\left(\frac{d y}{d x}\right)^2=\frac{r^2}{y-3}$