Ts Eamcet
Inverse Trigonometric Functions
TS EAMCET 2020 (Online) 14th September Evening Shift
MCQ+1 / -02020
If $\sum\limits_{n=1}^k \tan ^{-1}\left(\frac{1}{n^2+3 n+3}\right)=\tan ^{-1} \alpha$, then $\alpha=$
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