Chemical Kinetics

Given below is an expression for the rate constant of a first-order reaction occurring at a certain temperature, $\mathrm{T}(\mathrm{K})$.

\(\operatorname{lnk}=14.34-\frac{1.25 \times 10^4}{T}\)

The energy of activation in $\mathrm{kcal} \mathrm{mol}^{-1}$ for the reaction is :

(Given: $\mathrm{k}^{-1} \mathrm{~s} \mathrm{~s}^{-1}, \mathrm{R}=1.987 \mathrm{cal} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$ )