16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4e1,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2026 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2026/physics/waves/jt-mr4oxpek","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Waves","hasPart":{"@type":"Question","name":"Mht Cet 2026 Waves PYQ with Solution","text":"A tuning fork of frequency n produces x beats per second when sounded with a vibrating sonometer string. What must have been the frequency of the string, when a slight increase in tension produces lesser beats per second than before?","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"The beat frequency is equal to the difference between the frequencies of the two sources. Let the frequency of the sonometer string be f. Given tuning fork frequency = n and beats per second = x, |f-n|=x So the string frequency could be either f=n+x or f=n-x Now, when the tension in a sonometer string is slightly increased, its frequency increases because f \\propto \\sqrt{T} It is given that after increasing the tension, the number of beats becomes lesser. This means the string frequency must be..."}}}18:T400,

The beat frequency is equal to the difference between the frequencies of the two sources.

Let the frequency of the sonometer string be $f$.

Given tuning fork frequency $= n$ and beats per second $= x$,

$$ |f-n|=x $$

So the string frequency could be either

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