Mht Cet
Waves
MHT CET 2026 20th April Evening Shift
MCQ+1 / -02026
Two waves are represented as
$y_1 = a_1\sin\left(\omega t - \dfrac{2\pi x}{\lambda}\right)$ and
$y_2 = a_2\cos\left(\omega t - \dfrac{2\pi x}{\lambda} + \dfrac{\pi}{6}\right)$
The path difference between two waves is
$y_1 = a_1\sin\left(\omega t - \dfrac{2\pi x}{\lambda}\right)$ and
$y_2 = a_2\cos\left(\omega t - \dfrac{2\pi x}{\lambda} + \dfrac{\pi}{6}\right)$
The path difference between two waves is
