Mht Cet
Simple Harmonic Motion
MHT CET 2026 19th April Morning Shift
MCQ+1 / -02026
A particle executes a simple harmonic motion with a periodic time $8$ second. At time $t = 0$, it is at a mean position. The ratio of the distance traveled by a particle in the 2nd and that in the 1st second of its motion is
($\sin 45^\circ = \cos 45^\circ = \dfrac{1}{\sqrt{2}}$, $\sin 90^\circ = \cos 0^\circ = 1$)
($\sin 45^\circ = \cos 45^\circ = \dfrac{1}{\sqrt{2}}$, $\sin 90^\circ = \cos 0^\circ = 1$)