Mht CetRay OpticsMHT CET 2026 15th April Morning ShiftMCQ+1 / -02026An equiconvex lens of focal length F is cut in to two equal parts along the vertical axis. The focal length of each part will beA$4F$B$\dfrac{F}{2}$C$2F$D$F$Check AnswerClear SelectionReveal AnswerShow Explanation
