16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T543,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2026 Heat And Thermodynamics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2026/physics/heat-and-thermodynamics/jt-mr4o54nb","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Heat And Thermodynamics","hasPart":{"@type":"Question","name":"Mht Cet 2026 Heat And Thermodynamics PYQ with Solution","text":"A carnot engine having efficiency \\dfrac{1}{6}, operates between the source temperature T_H and the sink temperature T_C. Its efficiency increases to \\dfrac{1}{3}, when T_C is decreased by 64 K. The temperatures T_H and T_C are repectively","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"For a Carnot engine, efficiency is \\eta = 1 - \\frac{T_C}{T_H} Initially, the efficiency is \\dfrac{1}{6}. So, \\frac{1}{6} = 1 - \\frac{T_C}{T_H} \\frac{T_C}{T_H} = \\frac{5}{6} So, T_H = \\frac{6}{5}T_C Now the sink temperature is decreased by 64 \\, \\text{K}, so the new sink temperature is T_C - 64 The new efficiency is \\dfrac{1}{3}. So, \\frac{1}{3} = 1 - \\frac{T_C - 64}{T_H} \\frac{T_C - 64}{T_H} = \\frac{2}{3} Substitute T_H = \\dfrac{6}{5}T_C: \\frac{T_C - 64}{\\frac{6}{5}T_C} = \\frac{2}{3} \\frac{5(T_..."}}}18:T450,

For a Carnot engine, efficiency is

$$ \eta = 1 - \frac{T_C}{T_H} $$

Initially, the efficiency is $\dfrac{1}{6}$.

So,

$$ \frac{1}{6} = 1 - \frac{T_C}{T_H} $$

Heat And Thermodynamics

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