Mht CetHeat And ThermodynamicsMHT CET 2026 19th April Evening ShiftMCQ+1 / -02026Assuming the expression for the pressure exerted by the gas, it can be shown that pressure isA$\left(\dfrac{2}{3}\right)^{rd}$ of kinetic energy per unit volume of a gas.B$\left(\dfrac{3}{4}\right)^{th}$ of kinetic energy per unit volume of a gas.C$\left(\dfrac{1}{3}\right)^{rd}$ of kinetic energy per unit volume of a gas.D$\left(\dfrac{3}{2}\right)^{nd}$ times kinetic energy per unit volume of a gas.Check AnswerClear SelectionReveal AnswerShow Explanation
