16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4e0,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2026 Fluid Mechanics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2026/physics/fluid-mechanics/jt-mr4ofhak","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Fluid Mechanics","hasPart":{"@type":"Question","name":"Mht Cet 2026 Fluid Mechanics PYQ with Solution","text":"The excess pressure inside the first soap bubble of radius R_1 is three times that inside the second soap bubble of radius R_2. The ratio of volumes of the first to second bubble is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"For a soap bubble, the excess pressure inside it is \\Delta P = \\frac{4T}{R} where T is the surface tension and R is the radius of the bubble. For the first bubble, \\Delta P_1 = \\frac{4T}{R_1} For the second bubble, \\Delta P_2 = \\frac{4T}{R_2} It is given that the excess pressure inside the first bubble is three times that inside the second bubble: \\Delta P_1 = 3\\Delta P_2 So, \\frac{4T}{R_1} = 3 \\times \\frac{4T}{R_2} Cancel 4T from both sides: \\frac{1}{R_1} = \\frac{3}{R_2} So, R_2 = 3R_1 Now, vo..."}}}18:T40b,

For a soap bubble, the excess pressure inside it is

$$ \Delta P = \frac{4T}{R} $$

where $T$ is the surface tension and $R$ is the radius of the bubble.

For the first bubble,

$$ \Delta P_1 = \frac{4T}{R_1} $$

For the second bubble,

$$ \Delta P_2 =

Fluid Mechanics

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