Mht Cet
Circular Motion
MHT CET 2026 11th April Morning Shift
MCQ+1 / -02026
The position vector of a particle is $\vec{r} = a \cos \omega t \hat{i} + a \sin \omega t \hat{j}$. Calculate the angle between its position vector and the velocity vector.
($\cos 0=1, \cos 90=0, \cos 60=0.5, \sin 30=0.5, \sin 0=0$)
($\cos 0=1, \cos 90=0, \cos 60=0.5, \sin 30=0.5, \sin 0=0$)
