Mht CetAtoms And NucleiMHT CET 2026 19th April Evening ShiftMCQ+1 / -02026The de-Broglie wavelength of an electron moving in the $n^{th}$ Bohr orbit of radius 'r' isA$n\pi r$B$\dfrac{nr}{\pi}$C$\dfrac{2\pi r}{n}$D$\dfrac{nr}{2\pi}$Check AnswerClear SelectionReveal AnswerShow Explanation
