Mht CetVector AlgebraMHT CET 2026 11th April Morning ShiftMCQ+2 / -02026Let $A(2,3,0)$, $B(0,3,2)$ and $C(4,0,3)$ be vertices of a triangle, then the area of the triangle isA$\dfrac{\sqrt{171}}{2} \text{ sq. units}$B$\dfrac{\sqrt{172}}{2} \text{ sq. units}$C$\dfrac{\sqrt{173}}{2} \text{ sq. units}$D$\dfrac{\sqrt{174}}{2} \text{ sq. units}$Check AnswerClear SelectionReveal AnswerShow Explanation
