Mht CetTrigonometric EquationsMHT CET 2026 16th April Evening ShiftMCQ+2 / -02026The general solution of the equation $\cot\theta \cdot \cot 2\theta = 1$ is...A$\theta = n\pi \pm \dfrac{\pi}{6}, n \in Z$B$\theta = n\pi \pm \dfrac{\pi}{3}, n \in Z$C$\theta = n\pi \pm \dfrac{\pi}{4}, n \in Z$D$\theta = n\pi \pm \dfrac{\pi}{8}, n \in Z$Check AnswerClear SelectionReveal AnswerShow Explanation
