Mht Cet

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MHT CET 2026 13th April Evening Shift

MCQ+2 / -02026

It is known that a box of $8$ batteries contains $3$ defective pieces and a person randomly selects $2$ batteries from this box. Then the probability distribution of the number of defective batteries is

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$X = x$	$0$	$1$	$2$
$P(X = x)$	$\dfrac{10}{28}$	$\dfrac{15}{28}$	$\dfrac{3}{28}$

$X = x$	$1$	$2$	$3$
$P(X = x)$	$\dfrac{10}{28}$	$\dfrac{15}{28}$	$\dfrac{3}{28}$

$X = x$	$0$	$1$	$2$
$P(X = x)$	$\dfrac{15}{28}$	$\dfrac{10}{28}$	$\dfrac{3}{28}$

$X = x$	$1$	$2$	$3$
$P(X = x)$	$\dfrac{15}{28}$	$\dfrac{10}{28}$	$\dfrac{3}{28}$

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