Mht Cet
Probability
MHT CET 2026 15th April Evening Shift
MCQ+2 / -02026
A random variable X has the following probability distribution
For the event E = { X is a prime number } and F = { X < 4 }, P(E$\cup$F) =
| X | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| P(X=$x$) | 0.15 | 0.23 | 0.12 | 0.10 | 0.20 | 0.08 | 0.07 | 0.05 |
For the event E = { X is a prime number } and F = { X < 4 }, P(E$\cup$F) =