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Limits Continuity And Differentiability

MHT CET 2026 13th April Evening Shift

MCQ+2 / -02026
If $f(x)$ is continuous at $x = 0$, where $f(x) = \dfrac{8^x - 2^x}{k^x - 1}$, for $x \neq 0$ and $f(0) = 2$, then the value of $k$ is ...

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