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Inverse Trigonometric Functions

MHT CET 2026 15th April Morning Shift

MCQ+2 / -02026
If $\tan^{-1}\left[\dfrac{\sqrt{5-2\sqrt{6}}}{1+\sqrt{6}}\right] = \dfrac{\pi}{3} - \tan^{-1}(k)$, then $\sec^{-1}(k) = ...$

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