Mht CetInverse Trigonometric FunctionsMHT CET 2026 17th April Morning ShiftMCQ+2 / -02026The value of $3\tan^{-1}\left(\dfrac{1}{2}\right) = \ldots$A$\tan^{-1}\left(\dfrac{5}{2}\right)$B$\tan^{-1}\left(\dfrac{2}{5}\right)$C$\cot^{-1}\left(\dfrac{11}{2}\right)$D$\tan^{-1}\left(\dfrac{11}{2}\right)$Check AnswerClear SelectionReveal AnswerShow Explanation