Mht CetIndefinite IntegrationMHT CET 2026 11th April Evening ShiftMCQ+2 / -02026The value of $\int \dfrac{1}{x^2 - 5x + 8} dx$ is equal to...A$\dfrac{2}{\sqrt{7}}\tan^{-1}\left(\dfrac{2x+5}{\sqrt{7}}\right) + c$B$-\dfrac{2}{\sqrt{7}}\tan^{-1}\left(\dfrac{2x-5}{\sqrt{7}}\right) + c$C$\dfrac{2}{\sqrt{7}}\tan^{-1}\left(\dfrac{2x-5}{\sqrt{7}}\right) + c$D$-\dfrac{2}{\sqrt{7}}\tan^{-1}\left(\dfrac{2x+5}{\sqrt{7}}\right) + c$Check AnswerClear SelectionReveal AnswerShow Explanation
