Mht CetIndefinite IntegrationMHT CET 2026 16th April Morning ShiftMCQ+2 / -02026$\displaystyle\int \dfrac{(x + 1)(x + \log x)^2}{x}\,dx =$A$\left(\dfrac{x + \log x}{x}\right)^2 + c$, where c is the constant of integrationB$\dfrac{(x + \log x)^2}{x} + c$, where c is the constant of integrationC$\dfrac{(x + \log x)^3}{3} + c$, where c is the constant of integrationD$\dfrac{(x + \log x)^3}{3x} + c$, where c is the constant of integrationCheck AnswerClear SelectionReveal AnswerShow Explanation
