Mht CetIndefinite IntegrationMHT CET 2026 16th April Evening ShiftMCQ+2 / -02026$\int\dfrac{x^4 + 1}{x^6 + 1}dx = $A$\tan^{-1}x - \dfrac{1}{3}\tan^{-1}(x^3) + c$B$\tan^{-1}x + \dfrac{1}{3}\tan^{-1}(x^3) + c$C$\tan^{-1}x - \tan^{-1}(x^3) + c$D$\tan^{-1}x + \tan^{-1}(x^3) + c$Check AnswerClear SelectionReveal AnswerShow Explanation
