Mht CetIndefinite IntegrationMHT CET 2026 17th April Evening ShiftMCQ+2 / -02026If $\int f(x)\, dx = g(x)$ then $\int x^3 f(x^2)\, dx$ is equal toA$\dfrac{1}{2}\left[x^2 g(x^2) - \int g(x^2)\, d(x^2)\right]$B$\dfrac{1}{2}\left[x^2[f(x)]^2 - \int [g(x)]^2\, dx\right]$C$\dfrac{1}{2}\left[x^2 g(x) - \int g(x)\, d(x)\right]$D$\dfrac{1}{2}\left[x^2 g(x^2) + \int g(x^2)\, d(x^2)\right]$Check AnswerClear SelectionReveal AnswerShow Explanation
