Mht CetIndefinite IntegrationMHT CET 2026 19th April Morning ShiftMCQ+2 / -02026The value of integral $\displaystyle\int \dfrac{\sqrt{x^2 + 1}\,[\log(x^2 + 1) - 2\log x]}{x^4}\,dx$ is equal to...A$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) + \dfrac{2}{9}\right] + c$B$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) - \dfrac{2}{9}\right] + c$C$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) + \dfrac{2}{3}\right] + c$D$\left(1 + \dfrac{1}{x^2}\right)^{3/2}\left[\dfrac{-1}{3}\log\left(1 + \dfrac{1}{x^2}\right) - \dfrac{2}{3}\right] + c$Check AnswerClear SelectionReveal AnswerShow Explanation
