Mht CetIndefinite IntegrationMHT CET 2026 19th April Evening ShiftMCQ+2 / -02026If $u$ and $v$ are functions of $x$, then $\int \dfrac{1}{v^3}\left(uv\dfrac{du}{dx} - u^2\dfrac{dv}{dx}\right)dx = $A$\log uv + c$B$\log\dfrac{u}{v} + c$C$\dfrac{v^2}{2u^2} + c$D$\dfrac{u^2}{2v^2} + c$Check AnswerClear SelectionReveal AnswerShow Explanation
