Mht CetDifferentiationMHT CET 2026 13th April Evening ShiftMCQ+2 / -02026$\dfrac{d}{dx}\left[\sin^2\left\{\cot^{-1}\sqrt{\dfrac{1-x}{1+x}}\right\}\right] =$ ...A$-1$B$\dfrac{1}{2}$C$\dfrac{-1}{2}$D$1$Check AnswerClear SelectionReveal AnswerShow Explanation