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Differentiation

MHT CET 2026 15th April Evening Shift

MCQ+2 / -02026
If $e^y + xy = e$, then the ordered pair $\left(\dfrac{\text{d}y}{\text{d}x}, \dfrac{\text{d}^2 y}{\text{d}x^2}\right)$ at $x = 0$ is equal to

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