Mht CetDifferentiationMHT CET 2026 17th April Evening ShiftMCQ+2 / -02026If $y = \dfrac{1}{3x + 5}$, then the value of $\dfrac{d^9 y}{dx^9}$ is..A$\dfrac{9! \times 3^9}{(3x + 5)^9}$B$\dfrac{(-1)^8 \times 9! \times 3^9}{(3x + 5)^9}$C$\dfrac{(-1)^9 \times 9! \times 3^9}{(3x + 5)^{10}}$D$\dfrac{(-1)^8 \times 8! \times 3^9}{(3x + 5)^{10}}$Check AnswerClear SelectionReveal AnswerShow Explanation
