Mht CetDifferentiationMHT CET 2026 19th April Morning ShiftMCQ+2 / -02026If $y = \sin(2\sin^{-1} x)$ then $\dfrac{dy}{dx} =$..A$\dfrac{2 - 4x^2}{\sqrt{1 - x^2}}$B$\dfrac{2 + 4x^2}{\sqrt{1 - x^2}}$C$\dfrac{2 - 4x^2}{\sqrt{1 + x^2}}$D$\dfrac{2 + 4x^2}{\sqrt{1 + x^2}}$Check AnswerClear SelectionReveal AnswerShow Explanation
