Mht CetDifferential EquationsMHT CET 2026 13th April Morning ShiftMCQ+2 / -02026The solution of the differential equation $\dfrac{dy}{dx} = \dfrac{x+y}{x-y}$ isA$c(x^2 + y^2)^{\frac{1}{2}} + e^{\tan^{-1}\left(\frac{y^2}{x}\right)} = 0$, where c is an arbitrary constantB$c(x^2 + y^2)^{\frac{1}{2}} = e^{\tan^{-1}\left(\frac{y}{x}\right)}$, where c is an arbitrary constantC$c(x^2 - y^2) = e^{\tan^{-1}\left(\frac{y}{x}\right)}$, where c is an arbitrary constantD$c(x^2 + y^2) = e^{\tan^{-1}\left(\frac{y}{x}\right)}$, where c is an arbitrary constantCheck AnswerClear SelectionReveal AnswerShow Explanation
