Mht CetDifferential EquationsMHT CET 2026 17th April Evening ShiftMCQ+2 / -02026The general solution of the differential equations $\dfrac{dy}{dx} = (9x + y + 5)^2$ is...A$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = -2x + c$B$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = 2x + c$C$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = -3x + c$D$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = 3x + c$Check AnswerClear SelectionReveal AnswerShow Explanation
