Mht CetDefinite IntegrationMHT CET 2026 13th April Morning ShiftMCQ+2 / -02026If $\displaystyle\int_0^a \dfrac{dx}{1 + 4x^2} = \dfrac{\pi}{8}$, then $a =$A$\dfrac{1}{3}$B$\dfrac{1}{2}$C$\dfrac{1}{4}$D$1$Check AnswerClear SelectionReveal AnswerShow Explanation
