Mht CetApplication Of DerivativesMHT CET 2026 11th April Evening ShiftMCQ+2 / -02026The tangent to the curve $y^2 - xy + 9 = 0$ is vertical whenA$y = 0$B$y = \pm\sqrt{3}$C$y = \dfrac{1}{2}$D$y = \pm 3$Check AnswerClear SelectionReveal AnswerShow Explanation
