Mht CetApplication Of DerivativesMHT CET 2026 16th April Evening ShiftMCQ+2 / -02026The equation of tangent to the curves $x = 1 - 3t^2$ and $y = t - 3t^3$ at the point $(-2, 2)$ is...A$4x + 3y + 2 = 0$B$4x - 3y + 2 = 0$C$3x + 4y + 2 = 0$D$3x - 4y + 2 = 0$Check AnswerClear SelectionReveal AnswerShow Explanation