16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T506,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2026 Liquid Solution PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2026/chemistry/liquid-solution/jt-mr4ovio8","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Chemistry / Liquid Solution","hasPart":{"@type":"Question","name":"Mht Cet 2026 Liquid Solution PYQ with Solution","text":"A solution of 50g of solute 'X' is dissolved in 150 g of 'Y' solvent boils at 357.27 K. What is the molar mass of solute? (Given K_b and boiling point pure solvent is 2.77 K kg/mol and 350.06 K respectively.)","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"The elevation in boiling point is \\Delta T_b = T_b - T_b^\\circ Given, T_b = 357.27 \\, K T_b^\\circ = 350.06 \\, K So, \\Delta T_b = 357.27 - 350.06 = 7.21 \\, K For elevation in boiling point, \\Delta T_b = K_b \\times m where m is molality. So, m = \\frac{\\Delta T_b}{K_b} m = \\frac{7.21}{2.77} m \\approx 2.60 \\, mol \\, kg^{-1} Molality means moles of solute present in 1 kg of solvent. Here, mass of solvent Y = 150 \\, g = 0.150 \\, kg So, moles of solute X are \\text{moles of solute} = m \\times \\text{mas..."}}}18:T42e,

The elevation in boiling point is

$$ \Delta T_b = T_b - T_b^\circ $$

Given,

$$ T_b = 357.27 \, K $$

$$ T_b^\circ = 350.06 \, K $$

So,

$$ \Delta T_b = 357.27 - 350.06 = 7.21 \, K $$

For elevation in boil

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