Ionic Equilibrum

For basic solution, $[\text{H}_3\text{O}^+] = [\text{OH}^-]$

In basic solution, the excess of $\text{OH}^-$ ions are present.

In the basic solution, there is excess of $\text{H}_3\text{O}^+$ ions.

The pOH of a basic solution can be calculated by pOH = $-\log[\text{H}^+]$